« Back
Home /
Hydroxy ipronidazole-d3

Hydroxy ipronidazole-d3

Item no.	HY-135212S-2.5mg
Manufacturer	MedChem Express
CASRN	1156508-86-9
Amount	2.5 mg
Quantity options	10 mg 1 ea 1 mg 2.5 mg 25 mg 500 ug 5 mg
Category	Inhibitors & Compound Libraries Small Molecules
Type	Molecules
Specific against	other
Citations	[1]Russak EM, et al. Impact of Deuterium Substitution on the Pharmacokinetics of Pharmaceuticals. Ann Pharmacother. 2019;53(2):211-216. \|[2]Kamila Mitrowska, et al. Transfer of nitroimidazoles from contaminated beeswax to honey. Food Addit Contam Part A Chem Anal Control Expo Risk Assess.2017 Apr;34(4):573-581.
Smiles	CC(O)(C1=NC=C([N+]([O-])=O)N1C([2H])([2H])[2H])C
ECLASS 10.1	32169090
ECLASS 11.0	32169090
UNSPSC	12000000
Shipping Condition	Room temperature
Available
Manufacturer - Type	Isotope-Labeled Compounds
Manufacturer - Targets	Endogenous Metabolite; Isotope-Labeled Compounds
Shipping Temperature	Room temperature
Molecular Weight	188.20
Product Description	Hydroxy ipronidazole-d3 is the deuterium labeled Hydroxy ipronidazole. Hydroxy ipronidazole (Ipronidazole-OH) is a metabolite of nitroimidazole antibiotics, such as ipronidazole (IPZ). Hydroxy ipronidazole may has similar mutagenic potential as the parent compound[1].
Manufacturer - Research Area	Metabolic Disease
Solubility	10 mM in DMSO
Manufacturer - Pathway	Metabolic Enzyme/Protease; Others
Clinical information	No Development Reported

Note: The presented information and documents (Manual, Product Datasheet, Safety Datasheet and Certificate of Analysis) correspond to our latest update and should serve for orientational purpose only. We do not guarantee the topicality. We would kindly ask you to make a request for specific requirements, if necessary.

All products are intended for research use only (RUO). Not for human, veterinary or therapeutic use.

Request Data Sheet

Request product datasheet

Request safety datasheet

Simple Order Order Subscription

Amount: 2.5 mg

available

Compare

Add to wishlist

Get an offer

Request delivery time

Ask a technical question